1.00*sin34.3 = N* sin18.9
Solve for N, the index of refraction in the transparent solid material
N = 1.74
A ray of light of vacuum wavelength 550 nm traveling in air enters a slab of transparent material. The incoming ray makes an angle of 34.3◦ with the normal, and the refracted ray makes an angle of 18.9◦ with the normal. Find the index of refraction of the transparent material. (Assume that the index of refraction of air for light of wavelength 550 nm is 1.00.)
1 answer
1 answer