Looks like the function has (x-5) in the denominator, but not the numerator.
??/?(x-5)
It has (x-1) both top and bottom, because it's otherwise continuous there.
?(x-1)/(x-1)(x-5)
x=2 when y=0
(x-2)(x-1)/(x-1)(x-5)
limit is -1/9 at x=1
-4(x-2)(x-1)/9(x-1)(x-5)
f(0) = -8/45
as x gets large, f(x) approaches -4/9
A rational function f(x) contains quadratic functions in both the numerator and denominator. Also the function f(x) has a vertical asymptote at x=5, a single x intercept of (2,0) and f is removeably discontinuous at x=1 because the lim x-> 1 is -1/9.
Find f(0) and lim x-> infinity of F(x)
1 answer