A random sample of 250 men yielded 175 who said they'd ridden a motorcycle at some time in their lives, while a similar sample of 215 women yielded only 43 that had done so. Find a 99% confidence interval for the difference between the proportions of men and women who have ridden motorcycles.

Question

.4688 ± .085

.5 ± .112

.5 ± .103

.5 ± .085

.5 ± .078

Answer 1

Let's look at your data:
n1 = 250
n2 = 215
p1 = 175/250
p2 = 43/215

Formula:
CI99 = (p1 - p2) ± 2.58 √(p1(1-p1)/n1 + p2(1-p2)/n2)

Substitute the values into the formula and calculate. (Convert all fractions to decimals.)

You should be able to select your answer once you have determined the interval.

Answer 2

.5 ± .103

Answer 3

.5 �} .103, because, as the math guru said the formula is (p1 - p2) �} 2.58 �ã(p1(1-p1)/n1 + p2(1-p2)/n2), the 2.58 comes from the z-score table. The question doesn't want you to solve the whole formula, just the first and last.. (175/250)-(43/215)=.5 and the �ã(p1(1-p1)/n1 + p2(1-p2)/n2=.1026887336

Answer 4

Thank you. <3 @Math Whizz