Do you have typos?
Z = (score-mean)/SEm
SEm = SD/√n
Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion/probability related to the Z score. Relate to .03.
A random sample of 150 pumpkins is obtained and the mean circumference is found to be
45 cm. Assuming that the population standard deviation is known to be 1.8 cm, use a 0.03
significance level to test the claim that the mean circumference of all pumpkins is greater
than 38 cm.
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