Wc = mg = 600kg * 9.8N/kg = 5880 N. =
Wt of crate.
sinA = 1m/3m = 0.3333.
A = 19.47 Deg.
Fc = 5880N @ 19.47 Deg.
Fp = 5880*sin19.47 = 1960 N. = Force
parallel to plane.
W = Fp*d = 1960 * 3 = 5880 Joules.
A ramp leading up to a loading platform is 3 m long and 1 m high at its highest point. If the friction is ignored, what work is needed to slide a 600-kg crate up the ramp at a constant speed?
a) 2.00 *10^2 J
b) 5.89 *10^2 J
c) 1.80 *10^3 J
d) 5.88 *10^3 J
I believe the answer is d) but I would just like someone to explain the answer to me and correct me if d) isn't the answer. THANK YOU SO MUCH, in advance :)
1 answer