A rain cloud contains 2.66 x 10^7 kg of water vapor. How long will it take for a 2.00 kW pump to raise the same amount of water to the cloud's altitude, 2.00 km?
2 answers
timeinseconds=masswater*g*height/power
m=26600000kg
P=2000W
d=2000m
t=?
P=W/t=Fd/t
Forces that act on the object are Force that the pump applies (upward) and Fg (downward).
Fnet = F - Fg = 0, so F=Fg=26600000 *9.81
t=Fd/P=2.61*10^8 s
P=2000W
d=2000m
t=?
P=W/t=Fd/t
Forces that act on the object are Force that the pump applies (upward) and Fg (downward).
Fnet = F - Fg = 0, so F=Fg=26600000 *9.81
t=Fd/P=2.61*10^8 s
1 answer