A radio tower is 200 feet tall. How far is an observer from the base of the tower if the angle of their line of sight from the ground to the top of the tower is 65°

? Round to the nearest
hundredth.



(1 point)
The observer is
feet away.

1 answer

To find the distance from the observer to the base of the tower, we can use the tangent function from trigonometry. The tangent of an angle in a right triangle is the ratio of the opposite side to the adjacent side.

In this case:

  • The height of the tower (opposite side) is 200 feet.
  • The angle of elevation from the observer to the top of the tower is 65°.

Using the tangent function:

\[ \tan(65^\circ) = \frac{\text{opposite}}{\text{adjacent}} = \frac{200}{d} \]

where \( d \) is the distance from the observer to the base of the tower.

We can rearrange this equation to solve for \( d \):

\[ d = \frac{200}{\tan(65^\circ)} \]

Now we can calculate \( \tan(65^\circ) \):

\[ \tan(65^\circ) \approx 2.1445 \]

Now plug this into our equation for \( d \):

\[ d \approx \frac{200}{2.1445} \approx 93.23 \]

So, the distance from the observer to the base of the tower is approximately 93.23 feet.