A radio tower is 200 feet tall. How far is an observer from the base of the tower if the angle of their line of sight from the ground to the top of the tower is 65°

65
°
? Round to the nearest hundredth.(1 point)
Responses

428.90 ft
428.90 ft

93.26 ft
93.26 ft

23.66 ft
23.66 ft

178.57 ft

1 answer

To find the distance from the observer to the base of the tower, we can use the tangent function from trigonometry, which relates the angle of elevation, the height of the tower, and the distance from the observer.

The formula we will use is:

\[ \tan(\theta) = \frac{\text{opposite}}{\text{adjacent}} \]

Where:

  • \(\theta\) is the angle of elevation (65°)
  • The opposite side is the height of the tower (200 ft)
  • The adjacent side is the distance from the observer to the base of the tower (which we want to find).

Rearranging the formula to find the adjacent side gives us:

\[ \text{adjacent} = \frac{\text{opposite}}{\tan(\theta)} \]

Substituting in our values:

\[ \text{adjacent} = \frac{200 \text{ ft}}{\tan(65°)} \]

Now we calculate \(\tan(65°)\):

\[ \tan(65°) \approx 2.1445 \]

Now plug this into the calculation for adjacent:

\[ \text{adjacent} \approx \frac{200 \text{ ft}}{2.1445} \approx 93.26 \text{ ft} \]

Therefore, the distance from the observer to the base of the tower is approximately 93.26 ft.

Thus, the correct answer is:

93.26 ft.