A racquet ball with mass m = 0.224 kg is moving toward the wall at v = 14.8 m/s and at an angle of è = 27° with respect to the horizontal. The ball makes a perfectly elastic collision with the solid, frictionless wall and rebounds at the same angle with respect to the horizontal. The ball is in contact with the wall for t = 0.077s.


What is the magnitude of the change in momentum of the racquet ball?

1 answer

(0.224 kg)(14.8 m/s)*cos(27°)
=2.954 kg*m/s
The change in momentum is -2*2.954 kg*m/s, so the magnitude of the change is 5.91 kg*m/s.