d = Xo*t = 1.94, 4.8 * t = 1.94, t = 0.404 s.
h = 0.5g*t^2 = 4.9 * (0.404)^2 = 0.80 m.
A racquet ball is struck in such a way that it leaves the racquet with a speed of 4.8 m/s in the horizontal direction. When the ball hits the court, it is a horizontal distance of 1.94 m from the racquet. Find the height of the racquet ball when it left the racquet.
I need help setting up the problem. I think you're supposed to use vectors but I am not sure how to set it up with velocity vs distance because it does not make sense to have them on the same triangle if they are in different unit.
1 answer
1 answer