A racehorse is running at 42 miles per hour, equivalent to 18.8 meters per second. The horse and its jockey have a combined mass of 512 kilograms. How much kinetic energy do they have?

KE=12mv2


(1 point)
Responses

180.961.3 J
180.961.3 J

451,584.0 J
451,584.0 J

4,812.8 J
4,812.8 J

90,480.6 J

1 answer

The kinetic energy (KE) of an object can be calculated using the formula:

\[ KE = \frac{1}{2} mv^2 \]

where:

  • \( m \) is the mass (in kilograms)
  • \( v \) is the velocity (in meters per second)

Given:

  • Mass \( m = 512 \) kg
  • Velocity \( v = 18.8 \) m/s

Substituting the values into the formula:

\[ KE = \frac{1}{2} \times 512 \times (18.8)^2 \]

First, calculate \( (18.8)^2 \):

\[ (18.8)^2 = 353.44 \]

Now plug that value into the KE formula:

\[ KE = \frac{1}{2} \times 512 \times 353.44 \] \[ KE = 256 \times 353.44 \] \[ KE \approx 90,480.64 , \text{J} \]

Rounded to one decimal place, the kinetic energy is approximately:

\[ KE \approx 90,480.6 , \text{J} \]

Therefore, the answer is:

90,480.6 J