The centripetal part of the acceleration is
a,c = r w^2 = (29.3)*(0.621)^2 = 11.32 m/s^2
It is directed toward the center of the circle. The tangential acceleration a,t is such that
a,t/a,c = tan 35 = 0.700
The tangential acceleration is therefore
a,t = 16.17 m/s^2
The total acceeration a is such that
(a,c)/ a = sin 35
a = 19.74 m/s^2
A race car, starting from rest, travels around a circular turn of radius 29.3 m. At a certain instant, the car is still accelerating, and its angular speed is 0.621 rad/s. At this time, the total acceleration (centripetal plus tangential) makes an angle of 35.0° with respect to the radius. (The situation is similar to that in Figure 8.15b.) What is the magnitude of the total acceleration?
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1 answer