We need to find the greatest common divisor of 90 and 72 to determine the maximum number of baby bunnies the rabbit can have. By finding the GCD, we will find the largest number of bunnies that the rabbit can divide the carrots and lettuce evenly among.
The prime factorization of 90 is 2 * 3^2 * 5.
The prime factorization of 72 is 2^3 * 3^2.
To find the GCD, we take the highest power of each common prime factor: 2^3 * 3^2 = 72.
Therefore, the rabbit must have 72 baby bunnies in order to divide the carrots and lettuce evenly. Answer: 72.
A rabbit is packing lunches for his children. He has 90 carrots and 72 leaves of lettuce. If he is giving each bunny the same number of carrots and the same number of leaves of lettuce, how many baby bunnies must he have? He will have no extra vegetables after he packs the lunches.(1 point)
Responses
18
18
3
3
6
6
9
1 answer