Seems like he'll get 1/4 of them right, and 3/4 of them wrong. So, I'd expect a score of
90*(1/4)*4 + 90*(3/4)(-1/4)
A quiz consists of 90 multiple-choice questions, each with 4 possible answers (A, B, C and D). For someone who makes random guess , A is the correct answer for all the questions. If each right answer carries 4 marks and each wrong answer gives -1/4 marks, what probable marks someone will get? Please give calculation
4 answers
This is the FOURTH time ANUP has asked this question.
How many different answers does he/she need??
How many different answers does he/she need??
I guess we'll just keep seeing the question until
(a) an answer appears that he likes
(b) the assignment is due
(c) he posts his own solution
(a) an answer appears that he likes
(b) the assignment is due
(c) he posts his own solution
LOL! You're probably right!