A quiz consists of 90 multiple-choice questions, each with 4 possible answers (A, B, C and D). For someone who makes random guess , A is the correct answer for all the questions. If each right answer carries 4 marks and each wrong answer gives -1/4 marks, what probable marks someone will get? Please give calculation

4 answers

Seems like he'll get 1/4 of them right, and 3/4 of them wrong. So, I'd expect a score of

90*(1/4)*4 + 90*(3/4)(-1/4)
This is the FOURTH time ANUP has asked this question.

How many different answers does he/she need??
I guess we'll just keep seeing the question until

(a) an answer appears that he likes
(b) the assignment is due
(c) he posts his own solution
LOL! You're probably right!