A quarterback throws a pass that is a perfect spiral. In other words, the football does not wobble, but spins smoothly about an axis passing through each end of the ball. Suppose the ball spins at 5.8 rev/s. In addition, the ball is thrown with a linear speed of 17 m/s at an angle of 53° with respect to the ground. If the ball is caught at the same height at which it left the quarterback's hand, how many revolutions has the ball made while in the air?

asked by sarah

14 years ago

1,190 views

0

0

1 answer

The time in the air is 2*Vsin53/g

Multiply that by 5.8 rev/s for the number of revolutions.

answered by drwls

0

2

Ask a New Question or answer this question.

Question

A quarterback throws a pass that is a perfect spiral. In other words, the football does not wobble, but spins smoothly about an axis passing through each end of the ball. Suppose the ball spins at 5.8 rev/s. In addition, the ball is thrown with a linear speed of 17 m/s at an angle of 53° with respect to the ground. If the ball is caught at the same height at which it left the quarterback's hand, how many revolutions has the ball made while in the air?

1 answer

The time in the air is 2*Vsin53/g

Multiply that by 5.8 rev/s for the number of revolutions.

drwls · Answer

The time in the air is 2*Vsin53/g Multiply that by 5.8 rev/s for the number of revolutions.