A quantity, y, varies directly as x. When y = 10, x = 6.

Find x when y = 14.

4.3
8.4
60
23.3

1 answer

Since \( y \) varies directly as \( x \), we can express their relationship with the equation:

\[ y = kx \]

where \( k \) is the constant of variation.

From the information given, when \( y = 10 \), \( x = 6 \). We can use this to find \( k \):

\[ 10 = k \cdot 6 \]

Solving for \( k \):

\[ k = \frac{10}{6} = \frac{5}{3} \]

Now that we have the constant \( k \), we can find \( x \) when \( y = 14 \):

\[ 14 = \frac{5}{3} x \]

To isolate \( x \), multiply both sides by \( \frac{3}{5} \):

\[ x = 14 \cdot \frac{3}{5} = \frac{42}{5} = 8.4 \]

Therefore, when \( y = 14 \), the value of \( x \) is

\[ \boxed{8.4} \]