A quadratic inequality opens upward, has a vertex at (−1,−1)

, passes through the point (0,1)
, and has a solid curve with shading below the curve.

Write the quadratic inequality that represents the description.

(1 point)
The quadratic inequality that represents the description is $$
.

1 answer

To write the quadratic inequality based on the provided information, let's start by establishing the quadratic function based on the vertex and the point it passes through.

A quadratic function can be expressed in vertex form as:

\[ f(x) = a(x - h)^2 + k \]

where \((h, k)\) is the vertex of the parabola. Given the vertex is \((-1, -1)\), we have:

\[ f(x) = a(x + 1)^2 - 1 \]

Next, we know that the parabola passes through the point \((0, 1)\). We can use this point to find the value of \(a\):

\[ 1 = a(0 + 1)^2 - 1 \]

\[ 1 = a(1) - 1 \]

\[ 1 + 1 = a \]

\[ 2 = a \]

Now, we can write the quadratic function:

\[ f(x) = 2(x + 1)^2 - 1 \]

Now, we want to write the corresponding inequality. Since the problem states that the shading is below the curve, we will write:

\[ f(x) \leq 0 \]

Thus, substituting \(f(x)\) in the inequality, we get:

\[ 2(x + 1)^2 - 1 \leq 0 \]

To conclude, the quadratic inequality that represents the description is:

\[ 2(x + 1)^2 - 1 \leq 0 \]