v = 0 + a t
so 2 m/s = a t so t = 2/a
d = 0 + (1/2) a t^2
1 = (1/2) a t^2
1 = (1/2) a (2/a)^2
1 = (1/2) (4/a)
a = 2 m/s^2
A pupil pushes a wheelbarrow carrying 30kg sand .it accelerates from rest to 2m/s in the distance of 1m.what is the acceleration?
1 answer