a pump fills a tank of capacity 300 m^3 in 5 hours.the tank is situated at a height of 20 m.if the efficiency of the tank is 65%. then calculate the power of the engine which has driven the pump.

Answer 1

work done=weight of water into tank*20m
power= work done/time
power=1/.65 * 300m^3*densitywater*g*20m/(5hr*3600sec/hr)