A public heath official wanted to know how often university students visit their student health centers due to illness or injury. The official took a nationwide random sample of 120 university students and found an average of (x bar) = 2.30 visits per student per year. It is known that sigma = 0.44. Construct a 95% confidence interval for the mean number of visits u by a university student to a health center due to illness or injury. Round all results to two decimals places.

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95% = mean ± 1.96 SEm

SEm = SD/√n

answered by PsyDAG

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A public heath official wanted to know how often university students visit their student health centers due to illness or injury. The official took a nationwide random sample of 120 university students and found an average of (x bar) = 2.30 visits per student per year. It is known that sigma = 0.44. Construct a 95% confidence interval for the mean number of visits u by a university student to a health center due to illness or injury. Round all results to two decimals places.

1 answer

95% = mean ± 1.96 SEm

SEm = SD/√n

Ask a New Question or answer this question.

PsyDAG · Answer

95% = mean ± 1.96 SEm SEm = SD/√n