To find the number of tetras that can be housed in the aquarium, we need to divide the total volume of water in the aquarium by the volume of water needed for each individual neon tetra.
The volume of water needed for each neon tetra is given as 10^(-4) liters.
The total volume of water in the aquarium is given as 10^6 liters.
So, the number of tetras that can be housed in the aquarium is:
(10^6) / (10^(-4)) = 10^(6 + 4) = 10^10
Therefore, the aquarium can house 10^10 neon tetras.
A public aquarium is being built to contain neon tetras. Each neon tetra needs of water. The aquarium will contain of water. How many tetras can it house? Write the answer in scientific notation.
1 answer