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A proton with kinetic energy 100 keV is moving in a plane perpindicular to a uniform magnetic field of magnitude 2.3 T. Find the radius of its orbit.

Not sure what equation to use or how to solve

2 answers

R =mv/eB,
m= mass of proton = 1.67•10^-27 kg,
e = charge of proton = 1.6•10^-19 C

1keV =1000•1.6•10^-19 =1.6•10^-16 J

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