Asked by Physics is a pain
A proton of mass mp = 1.67 x 10-27 kg and charge +e = 1.60 x 10-19 C is accelerated from rest through an electric potential of 400 kV. What is its final velocity?
Answers
Answered by
drwls
The acquired kinetic energy is
E = e*V = 6.4*10^14 J
Set that equal to (1/2) Mp*V^2 and solve for V (in m/s)
If the computed V were close to or greater than the speed of light, you would have to use a different relavistic formula, but it won't be close.
E = e*V = 6.4*10^14 J
Set that equal to (1/2) Mp*V^2 and solve for V (in m/s)
If the computed V were close to or greater than the speed of light, you would have to use a different relavistic formula, but it won't be close.
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