Ask a New Question

A proton is placed at rest in an electric field of 515 N/C. Calculate the speed of the proton 36.0 ns after being released

1 answer

force*time=change in moentum
Eq*time=mass*velcityChange

Ask a New Question or answer this question.

Similar Questions

. A proton is released from rest at point A in a uniform electric field that has a magnitude of . The proton undergoes a
1. 0 answers
A proton is released from rest in a uniform electric field. After the proton has traveled a distance of 10.0 cm, its speed is
1. 3 answers
A proton with mass 1.67×10−27 kg and charge 1.60×10−19 C accelerates from rest in a uniform electric field of strength 500
1. 5 answers
At1=0, a proton is projected in the positive x-direction into a region of a uniform electric field of E=-6x1051. The proton
1. 1 answer

more similar questions