Assuming a constant % growth rate,
P(t) = 1500 e^kt
P(15) = 3350, so
1500 e^15k = 3350
k = 1/15 ln(3350/1500) = .0536
P(3) = 1500 e^(.0536*3) = 1762
A protected area was stocked with 1500 deer of a certain species in 1995. The deer population in 2010 was found to be 3350 deer. Let t be the number of years after 1195. Find the deer population at t=3
1 answer
1 answer