v^2/r=g (mass doesn't matter)
v^2 = r*g
v = sqrt(r*g)
v= sqrt(50.5*9.81)
A proposed space station includes living quarters in a circular ring 50.5 m in diameter. At what angular speed should the ring rotate so the occupants feel that they have the same weight as they do on Earth?
5 answers
v^2/r =omega^2 r = g = 9.81 m/s^2
omega^2 = 9.81/50.5 (radians/sec)^2
omega^2 = 9.81/50.5 (radians/sec)^2
What DonHo wrote is correct, but it asks for omega, the angular speed
sorry, my formula is off
should be
v^2*r=g
v=sqrt(g/r)
should be
v^2*r=g
v=sqrt(g/r)
Ac = omega^2 R = V^2/R