A proposed space station includes living quarters in a circular ring 50.5 m in diameter. At what angular speed should the ring rotate so the occupants feel that they have the same weight as they do on Earth?

5 answers

v^2/r=g (mass doesn't matter)

v^2 = r*g

v = sqrt(r*g)
v= sqrt(50.5*9.81)
v^2/r =omega^2 r = g = 9.81 m/s^2

omega^2 = 9.81/50.5 (radians/sec)^2
What DonHo wrote is correct, but it asks for omega, the angular speed
sorry, my formula is off

should be

v^2*r=g

v=sqrt(g/r)
Ac = omega^2 R = V^2/R