Ask a New Question

a projectile's launch speed is five times its speed at maximum height.find the launch angle?

1 answer

u = speed * cos theta = speed horizontal which never changes

u/speed = cos theta = 1/5 = o.2

theta = coa^-1 ( 0.2) = 78.5 degrees

Ask a New Question or answer this question.

Similar Questions

physicsa projectile's launch speed is fives times its speed at maximum height. find the launch angle?
1. 1 answer
In a projectile motion, if we measure the maximumheight h and horizontal range R (1) How to get launch angle θ in terms of h
1. 2 answers
In a projectile motion, the horizontal range and the maximum height attained by the projectile are equal .A) what is the launch
1. 3 answers
A hobby rocket reaches a height of 72.3 m and lands 111 m from the launch point.What is the angle of launch?What is the launch
1. 2 answers

more similar questions