A projectile of mass 0.528 kg is shot from

Question

a cannon, at height 6.7 m, as shown in the
figure, with an initial velocity vi having a
horizontal component of 7 m/s.
The projectile rises to a maximum height
of 3.8 m above the end of the cannon’s barrel
and strikes the ground a horizontal distance
∆x past the end of the cannon’s barrel.
∆x
vi
51
◦
3.8 m
6.7 m
Find the magnitude of the initial vertical
velocity vector of the cannon-ball at the end
of the cannon’s barrel. The acceleration of
gravity is 9.8 m/s
2
Answer in units of m/s.

Answer 1

Vo[51o]
Xo = 7 m/s
Vo = ?

Xo = Vo*Cos51 = 7 m/s
Vo = 7/Cos51 = 11.12 m/s = Initial velocity.

Yo = Vo*sin51 = 11.12*sin51 = 8.64 m/s.