A projectile leaves the ground at an angle of 60degree to the horizontal.it initial kinetic energy is E. Neglecting air resistance, it kinetic energy at the highest point of the motion is

Answer 1

initial speed = s

initial ke =.5 m s^2 = E

u = s cos 60 forever
at top v=0 so
ke = .5 m u^2 = .5 m s^2 cos^2 60
which is E cos^2 60
= E/4