Initial vertical velocity component =
Vy,0 = Vo sin 30 = 12.5 m/s
Maximum height is reached when
Vy,o = 12.5 m/s = g*T
T = 1.276 s
Maximum height reached = (Vy,0/2)*T = 6.25*1.276 = 7.97 m
Range = Vo*cos30*(2*T) = 55.3 m
a projectile is thrown with the speed of 25 meter per seconds in a direction 30° above the horizontal.
-how high does it go.
-how long does it take to reach the maximum height.
-how long does it reach the Projectile along in the air.
-how far does it go.
1 answer
1 answer