A projectile is thrown upward so that it's distance (in feet) above ground after t seconds is given by h(t)=-10t^2+440t. What is its maximum height?

Answer 1

This is modelled by a downwards opening parabola.
h(t) = -10t^2 + 440t
= -10t(t - 44)

so the x-intercepts are 0 and 44, which means that the vertex lies half way between them
i.e. x = 22
find h(22)

This worked nicely since there was no constant.

Answer 2

ewan ko