a projectile is thrown from the ground with an initial velocity of 20.0 m/s at an angle of 40.0 degrees above the horizontal. find the projectile's maximum height, the time required to reach its maximum height, its velocity at the top of the trajectory, the range of the projectile, and the total time of flight

Answer 1

U=20m/s. Angle=40 degree.use the equation H=u^2 sin^2 @/2g. Where H(height),u(initial velocity),sin@(angle of projection).