Height = -4.9t^2 + 120t
d(height)/dt = -9.8t +120
when t=5
velocity = -9.8(25)+120 = -120 m/s
A projectile is shot upward from the surface of the Earth with an initial velocity of 120 meters per second. What is its velocity after 5 seconds?
3 answers
Height = -4.9t^2 + 120t
d(height)/dt = -9.8t +120
when t=5
velocity = -9.8(25)+120 = -120 m/s
d(height)/dt = -9.8t +120
when t=5
velocity = -9.8(25)+120 = -120 m/s
Your answers are wrong. 71m/s
1 answer