A projectile is launched upward with a velocity of 128

Question

feet per second from the top of a 50- foot platform. What is the maximum height attained by the projectile?

Answer 1

g = -32 ft/s^2

so it take 4 seconds to reach max height ... 128 / 32 = 4

the average velocity is ... (128 + 0) / 2 = 64 ft/s

max height = 50 + (64 * 4)

Answer 2

306