Vo = 7550m/min @ 55.6deg.
Xo = hor. = 7550cos55.6 = 4265.5m/min.
Yo = ver. = 7550sin55.6 = 6229.6m/min.
A projectile is launched at an angle of 55.6 degrees to the horizontal and follows a straight path with a speed of 7550 m/min. Find the vertical and horizontale components of this velocity.
2 answers
69.2