A projectile is launched at 5.4 m/s with an initial angle of 22 degrees from an initial height of 2.6 meters. Where will it land? How fast, and at what angle will it be going when it hits the ground?

Answer 1

Vhoriz=5.4*cos22
Vivertical=5.4 sin22

hf=hi+viv*time-4.9t^2

you hf=0,solve for time, it is quadratic.
vvfinal=5.4sin22-gt solve for vfinal

angle when landing:
arctan (vvfinal/vhoriz)

velocityfinal=sqrt(vverfinal^2+vhor^2)