A projectile is given an initial velocity of (i + 2j) m/s, where i is along the ground and j is along the vertical. If g = 10 m/s2, the equation of its trajectory is:

Answer 1

v = 2 - 10 t
y = 2 t - 5 t^2

x = 1 t
so t = x

y = 2 x - 10 x^2