A projectile is fired with an initial velocity of 88 ft/sec at an angle of 35° to the horizontal. Neglecting air resistance, what is the time of impact? (Round to the nearest tenth of a second.)

Question

Remember: x = (v0 cos θ)t and y = h0 + (v0sinθ)t – 16 t^2

Answer 1

veryical velocity is 88sin35° = 50.47 ft/s

So,

y = 50.47t - 16t^2

set y=0 and solve for t.