A projectile is fired off a cliff at an angle of 60 degrees to the horizontal. The height of the cliff is 48 meters and the velocity of the projectile is 80 m/s. Find the range (dx)

Answer 1

in the vertical:
hv=hi+vi*t-4.8t^2
0=48+80*sin60*t-4.8t^2
solve for time t (use the quadratic equation)
then, range= 48*cos60*time

Answer 2

do I combine sin60*80 with 48 then take that product and multiply with t?