y = .5 a t^2 so
1.5 = .5*9.8 t^2. Solve for t.
b) x = vt so
3= v t (you got in part a)
a projectile is fired horizontally outward from the top of a table. the initial height of the bullet above the ground is 1.5 meters and the bullet travels a horizontal distance of 3.0 meters before striking the ground. Calculate the time bullet was in the air, B)muzzle(initial)velocity of the bullet
1 answer
1 answer