a projectile has an initial velocity of 15.0 m/s at an angle of 30 degrees above the horizontal. What is the location of the projectile 2.0 seconds later?

Answer 1

The time of flight of the projectle is
2 Vo*sin30/g = 1.53 seconds

After 2.0 seconds, it will have hit the ground already. Whether and how far it rolled after that I cannot say.

Answer 2

X = (V COSα)t
= 15*cos30*2

= 25.98