A projectile, fired with unknown initial velocity, lands 18.4 s later on the side of a hill, 3290 m away horizontally and 409 m vertically above its starting point. (Ignore any effects due to air resistance.)

Question

(a) What is the vertical component of its initial velocity?
112.38
(b) What is the horizontal component of its initial velocity?
178.8
(c) What was its maximum height above its launch point?
(d) As it hit the hill, what speed did it have and what angle did its velocity make with the vertical?

Answer 1

maximum height is when vertical velocity is zero, solve for that time, then find h.

for d) I would find vertical velocity when it hit, horizonal velocity, and add them as a vector. The angle can be found frm these two components.