A projectile fired from a gun has initial

Question

horizontal and vertical components of velocity equal to 30 m/s and 40 m/s, respectively. What is the speed of the projectile when it is at the highest point in its trajectory?
30 m/s
20 m/s
• 50 m/s
40 m/s
0 m/s

Answer 1

The speed of the projectile at the highest point in its trajectory can be calculated using the formula for total velocity:

Total velocity = √(horizontal velocity^2 + vertical velocity^2)

Substitute the given values:
Total velocity = √(30^2 + 40^2)
Total velocity = √(900 + 1600)
Total velocity = √2500
Total velocity = 50 m/s

Therefore, the speed of the projectile at the highest point in its trajectory is 50 m/s.