To determine the initial amount of bacteria, we evaluate the function \( s(n) = 20 \cdot b^n \) at \( n = 0 \):
\[ s(0) = 20 \cdot b^0 = 20 \cdot 1 = 20 \]
Thus, there were initially 20 bacteria.
Next, to calculate the hourly percent growth rate of the bacteria when \( b = 1.85 \), we can use the formula for growth rate:
\[ \text{Growth Rate} = (b - 1) \times 100% \]
Substituting \( b = 1.85 \) into the formula:
\[ \text{Growth Rate} = (1.85 - 1) \times 100% = 0.85 \times 100% = 85% \]
Therefore, the hourly percent growth rate of the bacteria would be 85%.