M of the diluted stuff is
1.14 g/mL x 1000 mL x 0.20 x 1/98 = 2.33M
M of the strong stuff is
1.84 x 1000 x 0.98 x 1/98 = 18.4M
Then use the dilution formula.
mLA x MA = mLB x MB
100 x 2.33 = mLB x 18.4M
Solve for mL B. I obtained approx 13 mL
A procedure calls for 100ml of 20% H2SO4, SG=1.14. How much of the concentrated acid (98%), SG=1.84, must be diluted with water to prepare 100ml of acid of the required strength?
1 answer