A pressurized can of whipping cream has an internal pressure of 1.035 atm at 28°C. If it is placed in a freezer at -15°C, what is the new value for its internal pressure?in atm

5 answers

(P1/T1) = (P2/T2)
Don't forget T must be in kelvin.
I set it up just like that and got kelvins right but still got it wrong
301.15k for T1
258.15k for T2

Answer was 0.887
P1 = 1.035 atm and T1 is 273.15 + 28 = 301.15
P2 = ? and T2 = -15 + 273.15 = 258.15

(1.035/301.15) = (P2/258.15)
P2 = 1.035*258.15/301.15 = 0.887
You must have made an error in solve that proportion. My answer seems to agree.
Sorry I wasn't clear. That was the answer I got. I think my sig figs wrong cause I don't see any with three.
You're right. It's a s.f. thing and I should have caught it. My answer is 0.887216 which I would round to 0.8872