(P1/T1) = (P2/T2)
Don't forget T must be in kelvin.
A pressurized can of whipping cream has an internal pressure of 1.035 atm at 28°C. If it is placed in a freezer at -15°C, what is the new value for its internal pressure?in atm
5 answers
I set it up just like that and got kelvins right but still got it wrong
301.15k for T1
258.15k for T2
Answer was 0.887
301.15k for T1
258.15k for T2
Answer was 0.887
P1 = 1.035 atm and T1 is 273.15 + 28 = 301.15
P2 = ? and T2 = -15 + 273.15 = 258.15
(1.035/301.15) = (P2/258.15)
P2 = 1.035*258.15/301.15 = 0.887
You must have made an error in solve that proportion. My answer seems to agree.
P2 = ? and T2 = -15 + 273.15 = 258.15
(1.035/301.15) = (P2/258.15)
P2 = 1.035*258.15/301.15 = 0.887
You must have made an error in solve that proportion. My answer seems to agree.
Sorry I wasn't clear. That was the answer I got. I think my sig figs wrong cause I don't see any with three.
You're right. It's a s.f. thing and I should have caught it. My answer is 0.887216 which I would round to 0.8872