A prep cook spins a salad spinner 25.0 times in 10.0 seconds (at a constant rate) and then stops. The salad spinner rotates 8.00 more times before it comes to rest. Assume that the spinner slows down with constant angular acceleration.

Question

What is the angular acceleration of the salad spinner as it comes to rest?

Answer 1

Divide 2 pi x 25 radians by 10 seconds for the initial angular velocity. I get 15.71 rad/s

Divide that angular rate by the time it takes to stop, to calculate the angular deceleration rate.

The time that it takes to stop is 16 pi radians divided by the average angular velocity. I get 6.40 s for that