Let's first write $n$ as $2^a \cdot p_1^{b_1} \cdot p_2^{b_2} \cdots p_k^{b_k},$ where $p_1, p_2, \ldots, p_k$ are distinct prime numbers and $a, b_1, b_2, \ldots, b_k$ are positive integers.
Since $n$ has exactly $9$ positive divisors, we know that $n$ can be written in the form $p_1^2 \cdot p_2^2 \cdot 2^2$ or $p^8$ where $p$ is a prime number.
If $n = p_1^2 \cdot p_2^2 \cdot 2^2,$ then the number of prime divisors of $n$ is $2.$
If $n = p^8,$ then the number of prime divisors of $n$ is $1.$
Therefore, there are $\boxed{3}$ prime numbers that are divisors of $n,$ namely $2, p_1, p_2.$
A positive integer is called nice if it is a multiple of $8.$
A certain nice positive integer $n$ has exactly $9$ positive divisors. How many prime numbers are divisors of $n?$
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