A population with μ = 59 and s = 8 is standardized to create a new distribution with μ = 100 and s = 20. After the transformation, an individual receives a new score of X = 90. The original score for this individual was X = 51.
True or False
3 answers
For this question I got true
Disagree.
Z = (score-mean)/SD = (51-59)/8 = -1
Z = (score-mean)/SD = (90-100)/20 = -.5
Z = (score-mean)/SD = (51-59)/8 = -1
Z = (score-mean)/SD = (90-100)/20 = -.5
true