A population of 100 moths has a gene that codes for wing color. Gray wings (G) are dominant to white wings (g). In this population, 20 percent of individuals are homozygous dominant for the trait, 20 percent are heterozygous, and 60 percent are homozygous recessive. Calculate allele frequencies for this population. State whether the population is in Hardy-Weinberg equilibrium, and justify your answer.

(4 points)

1 answer

To calculate the allele frequencies, we first need to determine the number of individuals with each genotype in the population.

Let's represent the dominant allele G and the recessive allele g.

Homozygous dominant (GG): 20% of 100 moths = 20 moths
Heterozygous (Gg): 20% of 100 moths = 20 moths
Homozygous recessive (gg): 60% of 100 moths = 60 moths

Now, we can calculate the allele frequencies:

Number of G alleles = 2*(number of GG moths) + 1*(number of Gg moths)
= 2*20 + 1*20 = 40 + 20 = 60

Number of g alleles = 2*(number of gg moths) + 1*(number of Gg moths)
= 2*60 + 1*20 = 120 + 20 = 140

Total number of alleles = 2*100 = 200

Frequency of G allele = Number of G alleles / Total number of alleles
= 60 / 200 = 0.3

Frequency of g allele = Number of g alleles / Total number of alleles
= 140 / 200 = 0.7

Therefore, the allele frequencies in this population are 0.3 for G and 0.7 for g.

To determine if the population is in Hardy-Weinberg equilibrium, we can use the formula:
p^2 + 2pq + q^2 = 1

where p is the frequency of the G allele and q is the frequency of the g allele.

Using the allele frequencies we calculated:
(0.3)^2 + 2*(0.3)*(0.7) + (0.7)^2
= 0.09 + 0.42 + 0.49
= 1

Since the sum is equal to 1, the population is in Hardy-Weinberg equilibrium. This means that the allele frequencies remain constant from generation to generation in the absence of evolutionary influences.